부스트코스 || count // tuple, sort, list comprehension

0. Counting Pattern

x = { 'a' :50, 'b' : 40, 'c': 60}
for aaa,bbb in x.items() :    #item's'
	print(aaa,bbb)


line = ' the the the i i i general pattetn to count the the words hehe'
words = line.split()
print(words)

counts = dict()
for word in words:
	counts[word] = counts.get(word,0) +1
print(counts)

bigcount = None
bigword = None
for word,count in counts.items():
	if bigcount is None or count > bigcount:
		bigword = word
		bigcount = count
print(bigword, bigcount

 

1. tuple, sort, list comprehension

x = ('glenn', 'maggie', 'sally')
print(x)

x = (40, 30, 40, 10)
print(x)
print(max(x))

# ()의 경우, 구성성분을 변경할 수 없음.
# [] 구성성분은 변경 가능.   ex) sort, append, reverse
# why do we use tuple? because it's more efficient.

(x,y) = (3, 'fred')
print(y)  # == fred
(a,b) = (99,0)
print(a) # == 99

if ('jones', 'saa') < ('jones', 'sab') :
	print('yes')


print( "\nsorted by key")
a= {'a':50, 'c':60, 'd':6, 'b':80}
a.items()
print(a.items())
print(sorted(a.items()))
for k,v in sorted(a.items()):
	print(k,v)


print("\nsort by values")
x={'a':10, 'b':30, 'c':90}	
y=list()
for k,v in x.items():
	y.append((v,k))     #: k,v 위치를 바꾼 값을 y이름의 list에 추가함(append)
print(y)

print("\n 위의 식과 아래의 식은 같음 -> aka [list comprehension]")
print(sorted([(v,k) for k,v in x.items()]))

print("\n정렬")
n=sorted(y,reverse=True)   #sorted(y, reverse=True) == y값을 내림차순 정렬
print(n)
m=sorted(y,reverse=False)  #sorted(y, reverse=False)  == y값을 오름차순 정렬
print(m)

 

- tuple, sort 연습

hand = open('ex_09_clown.txt')

di = dict()
for lin in hand:
	lin = lin.rstrip()
	wds = lin.split()
	for w in wds :
		di[w] = di.get(w,0) +1

print('\n', di)

x= di.items()
print('\n', x)

# 위의 값을 정렬하기
y = sorted(di.items())
print('\n', y)
print(y[:5])


a = list()
for k,v in di.items():
	print(k,v)
	newtup = (v,k)
	a.append(newtup)

print("\nflipped->", a)
a= sorted(a)
print('\nsorted->', a[:5])

for v,k in a[:5]: 
	print(k,v)